College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.7 - Properties of Matrices - 5.7 Exercises - Page 554: 37

Answer

$\begin{bmatrix} -4 &8\\0&6\end{bmatrix} $

Work Step by Step

When we multiply a scalar $k$ with a matrix $A$, then the product will be the matrix $kA$, each of whose elements is $k$ times the corresponding element of $A$. Thus, to find $2A$, we have to multiply $2$ to each element of $A$ to obtain: \begin{align*} 2A&=2 \begin{bmatrix} -2 &4\\0&3\end{bmatrix} \\ \\&=\begin{bmatrix} (2)(-2) &(2)(4)\\2(0)&(2)(3)\end{bmatrix}\\ \\&=\begin{bmatrix} -4 &8\\0&6\end{bmatrix} \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.