Answer
$\begin{bmatrix} -4 &8\\0&6\end{bmatrix} $
Work Step by Step
When we multiply a scalar $k$ with a matrix $A$, then the product will be the matrix $kA$, each of whose elements is $k$ times the corresponding element of $A$.
Thus, to find $2A$, we have to multiply $2$ to each element of $A$ to obtain:
\begin{align*}
2A&=2 \begin{bmatrix} -2 &4\\0&3\end{bmatrix} \\
\\&=\begin{bmatrix} (2)(-2) &(2)(4)\\2(0)&(2)(3)\end{bmatrix}\\ \\&=\begin{bmatrix} -4 &8\\0&6\end{bmatrix}
\end{align*}