College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Section 5.3 - Determinant Solution of Linear Systems - 5.3 Exercises - Page 512: 6

Answer

$-2$

Work Step by Step

The determinant for a $2 \times 2$ matrix $\begin{bmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \\ \end{bmatrix}$ can be defined as: $\text{det}= \begin{vmatrix} a_{11} & a_{12} \\ a_{21} & a_{22} \\ \end{vmatrix}=a_{11}a_{22}-a_{12}a_{21}$ Therefore, $\text{det}=\begin{vmatrix} 0 & 2 \\ 1 & 5 \\ \end{vmatrix}=(0)(5) -(2)(1) =0-2 =-2$ Therefore, the determinant of the given matrix is $-2$.
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