Answer
$\text{no solutions}$
Work Step by Step
We can write the systems of equations as:
$$y=-x+3 \quad \quad(a) \\2x+2y=1 \quad \quad(b)$$
Substitute $y=-x+3$ into Equation $(b)$ to obtain:
$$2x+2(-x+3)=1\\
2x-2x+6=1 \\
6=1$$
Since the result a false statement ($6$ is not equal to $1$), then the system has no solutions.
