College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 5 - Review Exercises - Page 575: 3

Answer

The system of equations has infinitely many solutions. Solution Set: $\left\{\left(-5y+9, y\right)\right\}$

Work Step by Step

We write the system of equations as: $$x+5y=9 \quad \quad\quad\quad(1)\\ 2x+10y=18 \quad \quad\space \space(2)$$ Multiply Equation $(1)$ by $-2$ to obtain the equivalent equation: $$-2x-10y=-18 \quad \quad(3)$$ Add Equations $(2)$ and $(3)$ to obtain: . $$(-2x-10y)+(2x+10y)=18-18 \\ 0=0 $$ Since both variables were eliminated and the resulting equation is true, then it follows that the system of equations has infinitely many solutions. To write the solution with $y$ arbitrary, solve for $x$ in equation $(1)$ to obtain: \begin{align*} x+5y&=9\\ x&=-5y+9\end{align*} Therefore, the solution set with $y$ arbitrary is $\left\{\left(-5y+9, y\right)\right\}$.
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