College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Test - Page 472: 13

Answer

$x=4$

Work Step by Step

Using the laws of exponents, the given equation, $ 16^{2x+1}=8^{3x} ,$ is equivalent to \begin{array}{l}\require{cancel} (2^4)^{2x+1}=(2^3)^{3x} \\\\ 2^{4(2x+1)}=2^{3(3x)} .\end{array} Since the bases are the same, the exponents can be equated. Hence, the solution is \begin{array}{l}\require{cancel} 4(2x+1)=3(3x) \\\\ 8x+4=9x \\\\ 8x-9x=-4 \\\\ -x=-4 \\\\ x=4 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.