Answer
$x=\pm125$
Work Step by Step
$$x^{\frac23}=25$$
$$\sqrt[3]{x^2}=25$$
$$(\sqrt[3]{x^2})^3=(25)^3$$
$$x^2=15625$$
$$x=\pm\sqrt{15625}=\pm\sqrt{25^2\cdot 25}=\pm(25\cdot 5)=\pm125$$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 4 - Test - Page 472: 10
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