College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises: 75

Answer

$x=4$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ \log_2(\log_2 x)=1 ,$ change to exponential form. Then do checking of the solution/s with the original equation. $\bf{\text{Solution Details:}}$ Since $\log_by=x$ is equivalent to $y=b^x$, the equation above, in exponential form, is equivalent to \begin{array}{l}\require{cancel} \log_2 x=2^1 \\\\ \log_2 x=2 .\end{array} Converting to exponential form again, the equation above is equivalent to \begin{array}{l}\require{cancel} x=2^2 \\\\ x=4 .\end{array} Upon checking, $ x=4 $ satisfies the original equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.