## College Algebra (11th Edition)

$x=4$
$\bf{\text{Solution Outline:}}$ To solve the given equation, $\log_2(\log_2 x)=1 ,$ change to exponential form. Then do checking of the solution/s with the original equation. $\bf{\text{Solution Details:}}$ Since $\log_by=x$ is equivalent to $y=b^x$, the equation above, in exponential form, is equivalent to \begin{array}{l}\require{cancel} \log_2 x=2^1 \\\\ \log_2 x=2 .\end{array} Converting to exponential form again, the equation above is equivalent to \begin{array}{l}\require{cancel} x=2^2 \\\\ x=4 .\end{array} Upon checking, $x=4$ satisfies the original equation.