College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 4 - Section 4.5 - Exponential and Logarithmic Equations - 4.5 Exercises - Page 447: 42



Work Step by Step

Changing to exponential form, the given expression, $ \log_5(8-3x)=3 $ is equivalent to \begin{array}{l}\require{cancel} 8-3x=5^3 \\\\ 8-3x=125 \\\\ -3x=125-8 \\\\ -3x=117 \\\\ x=\dfrac{117}{-3} \\\\ x=-39 .\end{array}
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