Answer
$\log_2{32}=5$
Work Step by Step
Given an exponential equation as: $b^x=a$
This equation can be converted into logarithmic form expressed as: $\log_b{a}=x$
Thus, $2^5=32$ is equivalent to $\log_2{32}=5$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 4 - Review Exercises - Page 468: 17
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