College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 3 - Review Exercises - Page 380: 86

Answer

$x=36$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use $ x=ky $ and solve for the value of $k$ with the given $ x $ and $ y $ values. Then use the equation of variation to solve for the value of the unknown variable. $\bf{\text{Solution Details:}}$ Since $x$ varies directly as $y,$ then $ x=ky .$ Substituting the given values, $ x=12 $ and $ y=4 ,$ then the value of $k$ is \begin{array}{l}\require{cancel} 12=k(4) \\\\ \dfrac{12}{4}=k \\\\ k=3 .\end{array} Hence, the equation of variation is given by \begin{array}{l}\require{cancel} x=ky \\\\ x=3y .\end{array} If $y=12,$ then \begin{array}{l}\require{cancel} x=3y \\\\ x=3(12) \\\\ x=36 .\end{array}
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