#### Answer

See the picture below.

#### Work Step by Step

By calculating the values of $f(x)=(x-4)^2$ (with blue) and $g(x)=x^2$ (with red) we can see that for every corresponding $f(x)$ and $g(x)$ value, each x value of $g(x)$ is 4 more than the x value of $f(x)$.
For drawing the exact parent graph, here is the table of values:
$g(-2)= -2^2=4$
$g(-1)= -1^2=1$
$g(0)= 0^2=0$
$g(1)= 1^2=1$
$g(2)=2^2=4$
Therefore the graph of $f(x)$ is exactly the same as the graph of $g(x)=x^2$ but translated 4 units right.
For drawing the exact graph of $f(x)$ here is the table of values of the given function:
$f(2)=(2-4)^2=4$
$f(3)=(3-4)^2=1$
$f(4)=(4-4)^2=0$
$f(5)=(5-4)^2=1$
$f(6)=(6-4)^2=4$