College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 186: 32


$3\sqrt{5}$ units

Work Step by Step

To find the distance between the two points, we use the distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ We plug in the points $(2,\ -3)$ and $(-1,3)$: $d=\sqrt{(-1-2)^{2}+(3--3)^{2}}$ $=\sqrt{(-3)^{2}+6^{2}}$ $=\sqrt{9+36}$ $=\sqrt{45}$ $=\sqrt{9*5}$ $=3\sqrt{5}$ Thus the distance and hence the radius is $3\sqrt{5}$.
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