College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 2 - Section 2.2 - Circles - 2.2 Exercises - Page 186: 31

Answer

$(2,-3)$

Work Step by Step

To find the midpoint, we use the midpoint formula: $\displaystyle Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$ $=(\frac{-1+5}{2},\frac{3+-9}{2})$ $=(\frac{4}{2},\frac{-6}{2})$ $=(2,-3)$
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