## College Algebra (11th Edition)

$(x+\sqrt 3)^{2}+(y+\sqrt 3)^{2}=3$
First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius. $(x-(-\sqrt 3))^{2}+(y-(-\sqrt 3))^{2}=\sqrt 3^{2}$ $(x+\sqrt 3)^{2}+(y+\sqrt 3)^{2}=3$