#### Answer

$x^{2}+y^{2}=36$

#### Work Step by Step

First, we put the given information into the center-radius equation for a circle given in the chapter. Place the $x$ value into the $h$ in the equation and the $y$ in the $k$. The $R$ is the radius.
$(x-0)^{2}+(y-0)^{2}=6^{2}$
$x^{2}+y^{2}=36$