Answer
$$x\geq-4$$
$$[-4,\infty)$$
Work Step by Step
$$-\frac{2}{3}x-\frac{1}{6}x+\frac{2}{3}x+\frac{2}{3}\leq\frac{4}{3}$$
$$-\frac{2}{3}x-\frac{1}{6}x+\frac{2}{3}x\leq\frac{2}{3}$$
$$(6)(-\frac{2}{3}x-\frac{1}{6}x+\frac{2}{3}x)\leq(6)(\frac{2}{3})$$
$$-4x-x+4x\leq4$$
$$-x\leq4$$
$$x\geq-4$$
