Answer
$$x\geq\frac{1}{2}$$
$$[\frac{1}{2},\infty)$$
Work Step by Step
$$\frac{2x-5}{-8}\geq 1-x$$
$$(-8)\frac{2x-5}{-8}\leq -8(1-x)$$
$$2x-5\leq-8+8x$$
$$-6x\leq-3$$
$$x\geq\frac{1}{2}$$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 1 - Section 1.7 - Inequalities - 1.7 Exercises - Page 146: 22
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