Chapter 1 - Section 1.6 - Other Types of Equations and Applications - Summary Exercises on Solving Equations - Page 136: 8

$x=6$

Multiplying both sides by the $LCD= 6 ,$ then the solution/s to the given equation, $ \dfrac{x}{2}+\dfrac{4}{3}x=x+5 ,$ is/are \begin{array}{l}\require{cancel} 3(x)+2(4x)=6(x)+6(5) \\\\ 3x+8x=6x+30 \\\\ 3x+8x-6x=30 \\\\ 5x=30 \\\\ x=\dfrac{30}{5} \\\\ x=6 .\end{array}