Answer
$a=\pm\sqrt{c^{2}-b^{2}}$
Work Step by Step
We solve for $a$:
$a^{2}+b^{2}=c^{2}$
Subtract $b^2$ to both sides:
$a^{2}=c^{2}-b^{2}$
Take the square root of both sides:
$a=\pm\sqrt{c^{2}-b^{2}}$
College Algebra (11th Edition)
by Lial, Margaret L.; Hornsby John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671791
ISBN 13:
978-0-32167-179-0
Chapter 1 - Section 1.6 - Other Types of Equations and Applications - Summary Exercises on Solving Equations - Page 136: 22
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