Answer
$$x=\frac{3}{5}$$
Work Step by Step
$$\frac{4x+3}{4}-\frac{2x}{x+1}=x$$
$$((4)(x+1))\frac{4x+3}{4}-\frac{2x}{x+1}=x((4)(x+1))$$
$$(4x+3)(x+1)-2x(4)=4x^2+4x$$
$$4x^2+4x+3x+3-8x=4x^2+4x$$
$$4x^2-x+3=4x^2+4x$$
$$-x+3=4x$$
$$-5x=-3$$
$$x=\frac{3}{5}$$
