College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.6 - Other Types of Equations and Applications - 1.6 Exercises - Page 134: 8



Work Step by Step

$$\frac{4x+3}{4}-\frac{2x}{x+1}=x$$ $$((4)(x+1))\frac{4x+3}{4}-\frac{2x}{x+1}=x((4)(x+1))$$ $$(4x+3)(x+1)-2x(4)=4x^2+4x$$ $$4x^2+4x+3x+3-8x=4x^2+4x$$ $$4x^2-x+3=4x^2+4x$$ $$-x+3=4x$$ $$-5x=-3$$ $$x=\frac{3}{5}$$
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