Answer
$$x=-\frac{7}{2},\frac{1}{3}$$
Work Step by Step
$$\frac{7}{x^2}-\frac{19}{x}=6$$
$$(x^2)(\frac{7}{x^2}-\frac{19}{x})=(x^2)(6)$$
$$7-19x=6x^2$$
$$0=6x^2+19x-7$$
$$(2x+7)(3x-1)=0$$
$$x=-\frac{7}{2},\frac{1}{3}$$
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