College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.3 - Complex Numbers - 1.3 Exercises - Page 104: 87

Answer

$-1$

Work Step by Step

Factor out as many $i^4$ as possible. $i^{22}=(i^4)^5*i^2$ Know that $i^4=1$. Substitute, and simplify. $(i^4)^5*i^2=1^5*i*i=1*-1=-1$
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