## College Algebra (11th Edition)

$(-2+i)^2+4(-2+i)+5=0$
In order to see that $-2+i$ is a solution, we plug it in and make sure the equation remains true. $(-2+i)^2+4(-2+i)+5=0?$ Expand the left hand side. $4-4i+i^2-8+4i+5$ Combine like terms using the fact that $i^2=-1$. $(-2+i)^2+4(-2+i)+5=0$