Answer
$\text{B and C}$
Work Step by Step
Solve each equation:
$\text{A}$
$2x+2(x-1)=14$
$2x+2(x)-1(2)=14$
$2x+2x-2=14$
$4x-2=14$
$4x-2+2=14+2$
$4x=16$
$\frac{4x}{4} =\frac{16}{4}$
$x=4$
$\text{B}$
$-2x+7(5-x)=52$
$-2x+7(5)-x(7)=52$
$-2x+35-7x=52$
$-9x+35=52$
$-9x+35-35=52-35$
$-9x=17$
$\frac{-9x}{-9}=\frac{17}{-9}$
$x=-\frac{17}{9}$ $\text{ (a length cannot be negative)}$
$\text{C}$
$5(x+2) +5x=10$
$5(x)+2(5)+5x=10$
$5x+10+5x=10$
$10x+10=10$
$10x+10-10=10-10$
$10x=0$
$\frac{10x}{10} =\frac{0}{10}$
$x=0$ $ \text{ (a length cannot be zero)}$
$\text{D}$
$2x+2(x-3) =22$
$2x+2(x)-3(2)=22$
$2x+2x-6=22$
$4x-6=22$
$4x-6+6=22+6$
$4x=28$
$\frac{4x}{4}=\frac{28}{4}$
$x=7$
