College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Section 1.2 - Applications and Modeling with Linear Equations - 1.2 Exercises - Page 93: 15


Width = 1.28 cm Length = 1.70 cm

Work Step by Step

Set up an equation for appropriate conditions. Factor out expression and add. Subtract .84. $2(x+.42)+2x=5.96$ Divide both sides by 4 and solve for x. $4x=5.12$ Solving for x gives you the value for width. Simply add .42 to find the value for length. Don't forget to check these values by substituting them into the original equation! $x=1.28cm(width)$, $x=1.70cm(length)$
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