College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter 1 - Review Exercises - Page 164: 80



Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ \sqrt[5]{2x}=\sqrt[5]{3x+2} ,$ raise both sides to the fifth power. Then isolate the variable. $\bf{\text{Solution Details:}}$ Raising both sides to the fifth power, the given equation is equivalent to \begin{array}{l}\require{cancel} 2x=3x+2 .\end{array} Using the properties of equality to isolate the variable results to \begin{array}{l}\require{cancel} 2x-3x=2 \\\\ -x=2 \\\\ x=-2 .\end{array}
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