## College Algebra (11th Edition)

Published by Pearson

# Chapter 1 - Review Exercises - Page 164: 79

#### Answer

$x=\left\{ -4,1 \right\}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $\sqrt{x^2+3x}-2=0 ,$ isolate the radical expression. Then square both sides and express in the form $ax^2+bx+c=0.$ Use concepts of solving quadratic equations to find the values of $x$. Finally, do checking of the solutions with the original equation. $\bf{\text{Solution Details:}}$ Using the properties of equality, the given equation is equivalent to \begin{array}{l}\require{cancel} \sqrt{x^2+3x}=2 .\end{array} Squaring both sides of the given equation results to \begin{array}{l}\require{cancel} x^2+3x=2^2 \\\\ x^2+3x=4 .\end{array} In the form $ax^2+bx+c=0,$ the equation above is equivalent to \begin{array}{l}\require{cancel} x^2+3x-4=0 .\end{array} Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the factored form of the equation above is \begin{array}{l}\require{cancel} (x+4)(x-1)=0 .\end{array} Equating each factor to zero (Zero Product Property) results to \begin{array}{l}\require{cancel} x+4=0 \\\\\text{OR}\\\\ x-1=0 .\end{array} Solving each equation results to \begin{array}{l}\require{cancel} x+4=0 \\\\ x=-4 \\\\\text{OR}\\\\ x-1=0 \\\\ x=1 .\end{array} Upon checking, $x=\left\{ -4,1 \right\}$ satisfy the original equation.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.