College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.7 - Rational Expressions - R.7 Assess Your Understanding - Page 70: 9

Answer

$\dfrac{x}{3}; x \ne 2$

Work Step by Step

Factor the numerator and the denominator completely to obtain: $=\dfrac{x(x-2)}{3(x-2)}$ Cancel the common factors to obtain: $\require{cancel} \\=\dfrac{x\cancel{(x-2)}}{3\cancel{(x-2)}} \\=\dfrac{x}{3}; x \ne 2$ ($x$ cannot be $2$ because it will make the original expression undefined.)
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