## College Algebra (10th Edition)

$\dfrac{x+5}{x-1};x \ne 1$
Factor the numerator and the denominator completely to obtain: $=\dfrac{(x+5)(x-1)}{(x-1)(x-1)}$ Cancel the common factors to obtain: $\require{cancel} \\=\dfrac{(x+5)\cancel{(x-1)}}{(x-1)\cancel{(x-1)}} \\=\dfrac{x+5}{x-1};x \ne 1$ ($y$ cannot be $1$ because it will make the original expression undefined.)