## College Algebra (10th Edition)

$−x^3+4x^2−4x−9$
$(x^2-3x-4)-(x^3-3x^2+x+5)$ To simplify, first distribute the negative sign to the contents of the parentheses on the right side. $(x^2-3x-4)-x^3+3x^2-x-5$ Now remove the remaining parentheses, and combine like terms. $x^2-3x-4-x^3+3x^2-x-5$= $−x^3+4x^2−4x−9$