College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.4 - Polynomials - R.4 Assess Your Understanding - Page 48: 32



Work Step by Step

$(x^2-3x-4)-(x^3-3x^2+x+5)$ To simplify, first distribute the negative sign to the contents of the parentheses on the right side. $(x^2-3x-4)-x^3+3x^2-x-5$ Now remove the remaining parentheses, and combine like terms. $x^2-3x-4-x^3+3x^2-x-5$= $−x^3+4x^2−4x−9$
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