The given expression is a polynomial whose degree is 0.
Work Step by Step
Using the rule $x^0=1$, the given expression is equivalent to: $=5(1) \\=5(x^0) \\=5x^0$ The exponent of the variable is $0$, which is a nonnegative integer. Thus, the given expression is a monomial and is consequently a polynomial. The degree of a nonzero polynomial in one variable is equal to the exponent of the variable. Thus, the degree of the polynomial is 0.