College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Test - Page 680: 16

Answer

See below.

Work Step by Step

The total weight lifted can be calculated by summing the first $5$ terms of the arithmetic sequence with $a_1=100$, $d=30$ multiplied by $10$, since there are $10$ repetitions in each set. The sum of the first $n$ terms of an arithmetic sequence can be obtained by the following formula: $\frac{n(a_1+a_n)}{2},$ where $a_1$ is the first term, $a_n$ is the nth term and $n$ is the number of terms. Thus $a_5=100+(5-1)30=220$. Thus $S_5=\frac{5(100+220)}{2}=800$. We have to multiply this by $10$, thus the total weight lifted is $8000$ pounds.
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