Answer
See below.
Work Step by Step
$s_1=\frac{1^2-1}{1+8}=\frac{0}{9}=0$
$s_2=\frac{2^2-1}{2+8}=\frac{3}{10}$
$s_3=\frac{3^2-1}{3+8}=\frac{8}{11}$
$s_4=\frac{4^2-1}{4+8}=\frac{15}{12}=\frac{5}{4}$
$s_5=\frac{5^2-1}{5+8}=\frac{24}{13}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 9 - Test - Page 680: 1
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