College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.2 - Arithmetic Sequences - 9.2 Assess Your Understanding - Page 655: 65

Answer

$\{T_{n}\}=\{67-5.5n\},$ $39.5^{o}F$

Work Step by Step

The temperatures are described as $\left\{\begin{array}{l} T_{1}=67\\ T_{n}=T_{n-1}-5.5 \end{array}\right.$, an arihmetic sequence with common difference $d=-5.5$, and terms representing temperatures at 1000 ft increments. The n-th term is $T_{n}=T_{1}+(n-1)d$ $T_{n}=67-5.5(n-1)$ The nth term here represents the temperature at (n-1)1000 ft. If we want it to represent n(1000) ft, then (the first term is $T_{0})$ and $T_{n}=67-5.5n$ 5000 ft is represented with $T_{5}$ $T_{5}=67-5.5(5)=39.5$
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