College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 9 - Section 9.2 - Arithmetic Sequences - 9.2 Assess Your Understanding - Page 655: 63

Answer

210 pink tiles, 190 blue tiles.

Work Step by Step

Pink tiles: Bottom row: 20 tiles, and one less for each following row. 20+19+18+...+2+1= sum of arithmetic sequence, $a_{1}=20,d=-1,n=20.$ $S_{n}=\displaystyle \frac{n}{2}\left(a_{1}+a_{n}\right)=10(20+1)=210$ Blue tiles: 19 in the bottom row, 1 in the top row: 19+18+...+2+1= sum of arithmetic sequence, $a_{1}=19,d=-1,n=19.$ $S_{n}=\displaystyle \frac{n}{2}\left(a_{1}+a_{n}\right)=\frac{19}{2}(19+1)=19(10)=190$
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