College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Test - Page 636: 7

Answer

See below.

Work Step by Step

$2\begin{bmatrix} 1& -1 \\ 0& -4 \\ 3&2 \end{bmatrix}+\begin{bmatrix} 4& 6 \\ 1& -3\\ -1&8 \end{bmatrix}=\begin{bmatrix} 2& -2 \\ 0& -8 \\ 6&4 \end{bmatrix}+\begin{bmatrix} 4& 6 \\ 1& -3\\ -1&8 \end{bmatrix}=\begin{bmatrix} 2+4& -2+6 \\ 0+1& -8-3 \\ 6-1&4+8 \end{bmatrix}=\begin{bmatrix} 6& 4 \\ 1& -11 \\ 5&12 \end{bmatrix}$
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