Answer
See below.
Work Step by Step
$y=x+1$, thus $2(x+1)^2-3x^2=5\\2(x^2+2x+1)-3x^2=5\\-x^2+4x-3=0\\x^2-4x+3=0\\(x-1)(x-3)=0$
Thus $x=1$, then $y=1+1=2$ or $x=3$, then $y=3+1=4$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Test - Page 636: 22
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