Answer
$x=-10$
Work Step by Step
We know that $a^b=a^c\longrightarrow b=c$ if $a\ne1,a\ne-1$ (which applies here).
Hence here $25^{x+3}=5^{x-4}\\(5^2)^{x+3}=5^{x-4}\\5^{2(x+3)}=5^{x-4}\\2(x+3)=x-4\\2x+6=x-4\\2x=x-10\\x=-10$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Section 8.8 - Linear Programming - 8.8 Assess Your Understanding - Page 632: 34
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