Answer
See below.
Work Step by Step
Let $m^{0.2}=x$, then our equation is $2x^2-x=1\\2x^2-x-1=0\\(2x+1)(x-1)=0$
Thus $x=1\\m^{0.2}=1\\m=1^5=1$ or $x=-0.5\\m^{0.2}=-0.5\\m=(-0.5)^5=-\frac{1}{32}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Section 8.8 - Linear Programming - 8.8 Assess Your Understanding - Page 632: 33
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