Answer
$x\geq0$
$x\leq6$
$y\geq0$
$y\leq5$
$y\leq-x+2$
Work Step by Step
There are two vertical lines: x=0 and x=6
The area is to the right of x=0, so $x\geq0$. It is to the left of x=6, so $x\leq6$.
There are two horizontal lines: y=0 and y=5.
The area is over y=0, so $y\geq0$. It is under y=5, so $y\leq5$.
There is a linear function with a slope of $m=\frac{0-2}{2-0}=\frac{-2}{2}=-1$ and a y-intercept of (0,2). Also, the area is under the line, so
$y\leq-x+2$
