Answer
$x\geq0$
$x\leq4$
$y\geq0$
$y\leq-x+6$
Work Step by Step
There are two vertical lines: x=0 and x=4
The area is to the right of x=0, so $x\geq0$, and it is to the left of x=4, so $x\leq4.$
There is one horizontal line: y=0
The area is above that line, so $y\geq0$.
There is a linear function with a slope of $m=\frac{2-6}{4-0}=\frac{-4}{4}=-1$ and a y-intercept of (0,6). The area is under the line, so the equation is:
$y\leq-x+6$.
