Answer
$\left[\begin{array}{rr}
{6}&{32}\\
{1}&{3}\\
{-2}&{-4}\end{array}\right]$
Work Step by Step
Let $A$ denote an $m$ by $\fbox{$r$}$ matrix and let $B$ denote an $\fbox{$r$}$ by $n$ matrix.
The product $AB$ is defined as the $m$ by $n$ matrix whose entry in row $i,$ column $j$
is the product of the $i$ th row of $A$ and the $j$ th column of $B$ .
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$A$ is a $3$ by $\fbox{$3$}$ matrix and B is a $\fbox{$3$}$ by $2$ matrix.
The product $AB$ is defined, and is a $3$ by $2$ matrix.
$AB=\left[\begin{array}{cc}
{4(2)+(-2)(1)+3(0)}&{4(6)+(-2)(-1)+3(2)}\\
{0(2)+1(1)+2(0)}&{0(6)+1(-1)+2(2)}\\
{-1(2)+0(1)+1(0)}&{-1(6)+0(-1)+1(2)}\end{array}\right]$
$=\left[\begin{array}{rr}
{6}&{32}\\
{1}&{3}\\
{-2}&{-4}\end{array}\right]$
