College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 557: 79

Answer

$x=100,$ $y=210,$ $z=190$

Work Step by Step

$\begin{cases}x+y+z=500\\ 150x+135y+110z=64250\\ 75x+135y+110z=56750 \end{cases}$ Multiplying the third equation by $-1$ and adding it to the first equation. $\begin{cases}150x+135y+110z=64250\\ -75x-135y-110z=-56750\\ -- -- -- -- -- --\\ 75x=7500 \end{cases}$ $x=100$. Replacing the $x$ in equations and multiplying the first equation by $-110$ and adding it to the second equation. $\begin{cases}-110y-110z=-44000\\ 135y+110z=49250\\ -- -- -- --\\ 25y=5250\end{cases}$ $y=210,$ $z=190$
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