College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 557: 75

Answer

$r = 6$% $Y=9000$

Work Step by Step

$0.06Y - 5000r = 240$ $0.06Y + 6000r = 900$ Multiply first equation by -1 and add to second equation to eliminate Y $-0.06Y + 5000r = -240$ $0.06Y + 6000r = 900$ $5000r + 6000r = -240 + 900$ $11000r = 660$ $r=0.06$ $0.06Y - 5000 \times 0.06 = 240$ $0.06Y - 300 = 240$ $0.06Y = 240 + 300$ $0.06Y = 540$ $Y=9000$ Plug the Y in one of the equations and evaluate r $r=0.06$
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