College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 8 - Section 8.1 - Systems of Linear Equations: Substitution and Elimination - 8.1 Assess Your Understanding - Page 556: 55

Answer

$\displaystyle \{(-3,\frac{1}{2},1)\}$

Work Step by Step

$\left\{\begin{array}{lllll} x & +2y & -z & =-3 & \\ 2x & -4y & +z & =-7 & /R_{2}=r_{2}-2r_{1}\\ -2x & +2y & -3z & =4 & /R_{3}=r_{3}+2r_{1} \end{array}\right.$ ... Eliminate $x$ in eq. 2 and 3 $\left\{\begin{array}{lllll} x & +2y & -z & =-3 & \\ & -8y & +3z & =-1 & \\ & +6y & -5z & =-2 & /R_{3}=4r_{3}+3r_{2} \end{array}\right.$ ... Eliminate y in equation 3 $\left\{\begin{array}{lllll} x & +2y & -z & =-3 & \\ & -8y & +3z & =-1 & \\ & & -11z & =-11 & \end{array}\right.$ $(3)\Rightarrow z=1$ $(2) \displaystyle \Rightarrow-8y=-3z-1\Rightarrow-8y=-4\Rightarrow y=\frac{1}{2}$ $(1)\Rightarrow x=-2y+z-3=-1+1-3=-3$ Solution set: $\displaystyle \{(-3,\frac{1}{2},1)\}$
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