Answer
See below.
Work Step by Step
$3y+y^2=6y\\y^2-3y=0\\y(y-3)=0$
Thus $y=0, x^2=0\rightarrow x=0$ or $y=3,x^2=9\rightarrow x=\pm3$.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Review Exercises - Page 635: 41
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