Answer
See below.
Work Step by Step
$2x+y+3=0\\y=-3-2x$
Thus $x^2+(-3-2x)^2=5\\x^2+9+12x+4x^2=5\\5x^2+12x+4=0\\(5x+2)(x+2)=0$
Thus $x=-0.4,y=-3-2(-0.4)=-2.2$ or $x=-2,y=-3-2(-2)=1$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 8 - Review Exercises - Page 635: 39
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