College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 7 - Section 7.3 - The Ellipse - 7.3 Assess Your Understanding: 6

Answer

$$(x-2)^2+(y+3)^2=1$$

Work Step by Step

We know that the equation of a circle in standard form is given by: $$(x-h)^2+(y-k)^2=r^2$$ Where (h, k) is the center of the circle and r is the radius. Thus, for a circle with a center C=(2, -3) and a radius r=1, the equation becomes: $$(x-2)^2+(y+3)^2=1$$
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