## College Algebra (10th Edition)

$$(x-2)^2+(y+3)^2=1$$
We know that the equation of a circle in standard form is given by: $$(x-h)^2+(y-k)^2=r^2$$ Where (h, k) is the center of the circle and r is the radius. Thus, for a circle with a center C=(2, -3) and a radius r=1, the equation becomes: $$(x-2)^2+(y+3)^2=1$$