Answer
$$
\\ (2,0) \ \text{and} \ (-2, 0)$$
$$\\(0, 4) \ \text{and} \ (0, -4) $$
Work Step by Step
$$y^2=16-4x^2$$
Set y=0 to find the x intercept:
$$16-4x^2=0
\\x^2=4
\\x= \pm 2
\\ (2,0) \\ \text{and} \\ (-2, 0)$$
Set x=0 to find the y intercept:
$$
y^2=16
\\y= \pm 4
\\(0, 4) \ \text{and} \ (0, -4) $$
