College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter 6 - Section 6.8 - Exponential Growth and Decay Models; Newton's Law: Logistic Growth and Decay Models - 6.8 Assess Your Understanding - Page 486: 7


See below.

Work Step by Step

a) $N(t)=N_0e^{kt}$ b) We know that $2x=xe^{k\cdot18}\\2=e^{18k}\\18k=\ln2\\k=\frac{\ln2}{18}\approx0.038508176697774739412068451192120920448638896353347514117$ Thus $N(24)=10000e^{0.038508176697774739412068451192120920448638896353347514117\cdot24}\approx25198$
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